Give the chemical reactions for the following conversions:
$(1)$ Glyoxal from acetylene
$(2)$ Glycol from bromoethane
$(1)$ Glyoxal from acetylene
$(2)$ Glycol from bromoethane
(N/A) $(1)$ Conversion of acetylene to glyoxal:
$3CH \equiv CH \xrightarrow{\text{Red hot Fe tube, } 873 \ K} C_6H_6 \text{ (Benzene)}$
$C_6H_6 \xrightarrow[(ii) Zn, H_2O]{(i) O_3} 3CHO-CHO \text{ (Glyoxal)}$
$(2)$ Conversion of bromoethane to glycol:
$CH_3CH_2Br \xrightarrow{\text{alc. KOH, } \Delta} CH_2=CH_2 \text{ (Ethene)}$
$CH_2=CH_2 \xrightarrow{\text{dil. } KMnO_4, 273 \ K} CH_2(OH)-CH_2(OH) \text{ (Ethane-1,2-diol or Glycol)}$
$3CH \equiv CH \xrightarrow{\text{Red hot Fe tube, } 873 \ K} C_6H_6 \text{ (Benzene)}$
$C_6H_6 \xrightarrow[(ii) Zn, H_2O]{(i) O_3} 3CHO-CHO \text{ (Glyoxal)}$
$(2)$ Conversion of bromoethane to glycol:
$CH_3CH_2Br \xrightarrow{\text{alc. KOH, } \Delta} CH_2=CH_2 \text{ (Ethene)}$
$CH_2=CH_2 \xrightarrow{\text{dil. } KMnO_4, 273 \ K} CH_2(OH)-CH_2(OH) \text{ (Ethane-1,2-diol or Glycol)}$
Explore More
Similar Questions
The compound formed by passing ethylene gas into a cold alkaline solution of $KMnO_4$ is:
Medium
View SolutionThe compound $CH_3-C(CH_3)=CH-CH_3$ on reaction with $NaIO_4$ in the presence of $KMnO_4$ gives:
MediumAIPMT 2003
View SolutionAt low temperatures,the slow addition of molecular bromine to $CH_2=CH-CH_2-C \equiv CH$ gives :-
Medium
View SolutionThe major products $P$ and $Q$ in the following reaction sequence are:
DifficultTS EAMCET 2020
View Solution${\text{Glycerol}}$ $\xrightarrow{KHSO_4} (A)$ $\xrightarrow{LiAlH_4} (B)$; $(A)$ and $(B)$ are respectively:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo